# Determine the reactions at the supports a and b of the compound beam there is a pin at c

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**A**C

**B**—L 2 —L 2 M 0 Solution

**Support**

**Reactions**.

**The**

**support**

**reactions**have been determined in Fig. 6-5d. Shear and Moment Functions.This problem is similar to the previous example, where two x coordinates must be used to express the shear and moment in the

**beam**throughout its length.For the segment within region AB,Fig.6-5b, we have.

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**BEAM**DIAGRAMS AND FORMULAS Table 3-23 (continued) Shears, Moments and Deflections 13.**BEAM**FIXED AT ONE END, SUPPORTED AT OTHER-CONCENTRATED LOAD AT CENTER- So from here
**B**y plus**C**y is 4.5 kg Newton and dy is six cologne Newton minus 18 g. So from here, the way comes out to be 75 kill you. Okay? No, similarly, we will grow the bar. Maybe this is a bar. This is point A and this is - A 2m
**C**2 kN/m 6m 45˚**B**D SOLUTION 3m 3m Support**Reactions Determine**the distance a in terms of the**beam**'s w0 w0 length L between the symmetrically placed**supports A and B**so that the internal moment at The center of - components of the force exerted at C on member BCD. SOLUTION: • Create a free-body diagram for the complete frame and solve for the
**support****reactions**. • Define a free-body diagram for member BCD. The force exerted by the link DE has a known line of action but unknown magnitude. It is determined by summing moments about C. - Search:
**Determine****The****Reactions****At****The****Supports****A****And****B**. 4 Assume the**supports****at****B****and**C are rollers and A is fixed nck) N ( TBD TBD (**b**, 7010 - 2j-2k 22±22 k -304 0 k -t N 0,707Tgp - -210408Tòl o 4308 10 1 The joint at**B****is**rigid The center of gravity of the crane is located at G 3**REACTIONS**coming from the**supports**3**REACTIONS**coming from the**supports**.